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    S-72.245 Transmission Methods inTelecommunication Systems (4 cr)

    Noise in analog carrier wave (CW) modulationsystems

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    Noise in analog CW modulation systems

    Understanding noise

    Lowpass presentation of bandpass noise and its conversionto baseband noise

    Noise statistics of quadrature presentation in rectangular and

    polar coordinates Modeling detectors for linear and exponential modulation

    Analysis of post-detection SNR

    Synchronous detector

    PM-detector

    FM-detector

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    Noise in carrier wave modulation

    systems:basic definitions

    Objectives: Define bandpass noise and use it to analyze postdetection SNR of analog CW systems

    Assume signal is ergodic, e.g., all ensemble averages E[] equalthe corresponding time averages . Then, for instance

    where the time average is defined by

    ( ) E[ ( )]v t v t 2 2( ) E[ ( )]v t v t

    ( ) ( ) E[ ( ) ( )]v t v t v t v t

    / 2

    / 2

    1( ) lim ( )

    T

    Ti iTv t v t dt

    T

    / 2

    / 2

    1( ) ( )

    T

    Ti iv t v t dt

    T (for a known period)

    or

    average valueaverage power

    autocorrelation

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    The system model

    We consider normalized ergodic analog message whoseamplitude and power are normalized2 2

    ( ) 1, ( ) , 1x x

    x t S x x t S Channel loss

    Modulated signal

    Transmitted powerReceived power

    Received signal (not altered by HR)

    Detector

    2/R T c

    S S L x

    Post-detection filter

    Pre-detection filter

    Pre-detection noise (after HR)

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    Detection models

    Pre-detection signal v(t) is presented in quadrature-carrier form:

    Detection models:

    ( ) ( )cos[ ( )]

    ( )cos( ) ( )cos( )

    v c v

    i c q c

    v t A t t t

    v t t v t t

    ( ) ( )cos ( )

    ( ) ( )sin ( )

    i v

    q v

    v t A t t

    v t A t t

    v

    ( ) Synchronous detector

    ( ) Envelope detector( )

    ( ) Phase detector

    ( ) / Frequency detector

    i

    v v

    v

    v t

    A t Ay t

    t

    d t dt

    0 0( ) cos[ 2 ( ) ], )

    t

    tC C Cx t A t f x d t t

    (Remember that FM was defined by:

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    Pre-detection noise in bandpass channel

    Signal and noise are statistically independent and therefore theirpower can be added to form the total pre-detection power:

    The pre-detection (bandpass) noise power is filtered from thechannel noise:

    2 2 2 c R R

    v x n S N

    2

    0( / 2) ( ) 2 ( / 2)T

    B

    R R TN H f df df B

    fromchannel

    to detector

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    Pre-detection SNR Pre-detection signal-to-noise ratio for bandpass channels is

    defined by

    Note that above BT is the transmission bandwidth passingchannel noise power to the detector

    For comparison, we can write the received signal-to-noise interms of baseband system (BW = W) SNR defined by

    and therefore also

    Note that always (limiting case is the SSB with BT= W)

    (We will see, however, that post detection SNR can be muchlarger than !)

    / /( )R R R T

    S N S B

    2

    ( / 2) ( )

    R T RN B H f df

    /( )R

    S W

    / /( ) ( / )( / ) /R R R T R T T

    S N S B S W W B W B

    TB W /

    R RS N

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    Bandpass noise:

    We assume stationary, zero mean Gaussian noise process forwhich

    Bandpass noise in terms of lowpass equivalent signals

    The in-phase and quadrature componentsare independent and hence

    Their average is zero and their average power is thesame:

    2 20,n R

    n n N

    ( ) ( )cos( ) ( )sin( )i c q cn t n t t n t t

    2 2 2

    i q Rn n n N

    ( ) ( ) 0i qn t n t

    0i q

    n n

    in

    qn

    nA

    n

    ( ) ( )cos[ ( )]n c n

    n t A t t t

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    Bandpass noise has Rayleigh distributed

    envelope and evenly distributed phase

    I-Q components of the bandpass noise can be presented inenvelope - phase format:

    The PDF of envelope is Rayleighdistributed defined by

    Therefore mean and variance for thebandpass noise are (integrate from above, how?)

    2 2 2 , arctanq

    n i q n

    i

    nA n n

    n

    2 2

    ( ) exp ( )2n

    n n

    A n n

    R R

    A Ap A u A

    N N

    2 2

    2

    2 2 2 2

    2

    / 2, 2

    / 2 ( ) / 2i q

    n R n R

    R n i qn n n

    A N A N

    N A n n n

    in

    qn

    nA

    n

    Two independentr.v.:s - sum of theirvariances equals varianceof the envelope

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    Post detection noise in synchronous detection

    Signal component of synchronous detector:

    Noise component of synchronous detector:

    Detector extracts i-components and removes double frequencycomponents

    ( ) ( )exp( )

    ( ) ( )cos( ) ( )sin( )

    ( )( )cos( )

    2( ) ( )cos(2 ) sin(2 )

    2 2

    DSB c

    DSB c c c c

    c

    DSB c

    c c

    c c

    v t x t j t

    v t A x t t jA x t t

    A x tv t t

    A x t A x tt j t

    ( )cos( ) cos( ) ( )cos( ) ( )sin( )

    cos(2 ) / 2 ( )si( ) 1 n(2 ) / 2

    c c i c q c

    ci q c

    n t t t n t t n t t tn t tt n

    ( ) ( ) ( )D c i

    y t A x t n t cos( )cos( ) 1/2 cos(2 )/ 2

    cos( )sin( ) sin(2 )/ 2

    x x x

    x x x

    detected message

    received DSB signal

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    Post-detection SNR for DSB

    Obtain signal and noise power after detection from:

    where average noise and signal power are

    Received average signal power is

    and therefore SNR after DSB detector is

    ( ) ( ) ( )D c i

    y t A x t n t

    2 2 2 2

    ( ) , ( ) D i D c c x

    N n t S A x t A S

    2 2 2 2 2

    0

    1/ 2

    ( ) cos ( ) / 2 2 / x

    R c c x x R c

    S

    S A x t t A S S S A

    2

    2

    / /D D c D

    c

    xSS N A N

    A

    2

    2R

    c

    S

    A2 (DSB)

    2 2(DSB)

    T

    R R R

    D B WD T

    S S S

    WN BN

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    Comparing SNR for DSB and AM

    It can be show, that for AM the post detection SNR is

    Comparison of this to the SNR of DSB can done by noting that

    in practice

    Hence AM performs usually much worse than DSB

    It can be shown that for SSB performance is the same as for

    DSB, e.g.

    /1

    x

    D D AM

    x

    SS N

    S

    x

    0.5 tone modulation

    S 0.1 speech signal

    xS

    ,/ R

    D D USB DSB

    SS N

    W

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    Exponential modulation and channel noise

    Both PM and FM have constant envelopes so the receivedpower is constant

    Received SNR is yielding for wideband FM

    where for wideband modulation

    2 2

    ( ) cos[ ( )]

    / 2

    c c c

    R c c

    x t A t t

    S x A

    22

    22

    R c c

    R R T

    A

    N N B

    S A

    1,2( 2) 2

    2

    mT m f W

    B f W

    DW

    2 2

    R R

    R T

    RS S

    N B DW D

    S

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    Detection of exponential modulation

    assuming small noise power

    ( )sin[ ( )]( ) arctan

    ( )cos[ ( )]

    n n

    v

    c n n

    A t tt

    A A t t

    carrier+noise

    noise

    ( ) cos[ ( )] ( )cos[ ( )]c c n c n

    Signal Noise

    v t A t t A t t t

    ( )sin[ ( )]( ) n n

    v

    c

    A t tt

    A

    small compared to Ac

    Detected noise component

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    Post-detection noise spectra for PM

    The channel noise is bandpass noise filtered at the transmissionbandwidth and therefore the respective post-detection noise powerspectral density GPM(f) and the total noise power NDare

    ( )sin ( )( )

    ( )

    2

    n nv

    c

    q

    R

    A t tt A

    n t

    S

    2

    2 2

    / 2

    sinR c

    q n n

    i q R LP

    S A

    n A

    n n N B

    2

    ( )( )

    2

    2

    q

    PMTR

    R T

    n t fG f

    BS

    f

    S B

    Note that afterdetection signalbandwidth is Wandthus a post detectionfilter is required to removeout-of-band channel noise

    ( ) /W

    WD PM R

    N G f df W S

    LPB

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    Post-detection SNR for FM

    Recall the definition of FM-signal

    Frequency discriminator (detector) differentiates theinstantaneous phase to cancel out the inherent integration inphase. Now

    Inspection in frequency domain (In order to find the respectivePSDs) yields after detector

    and the signal PSD is

    ( ) 2 ( ) ( ) / v

    t x t d t dt

    ( )( ) 1 ( ) ( ) 1 ( )( )2 2 2 2

    qv S N S

    R

    Signal Noise

    d n td t d t d t d t x tdt dt dt dt S dt

    ( ) 2 ( )v

    X f j f f

    2

    ( ) ( ) ( 2FM

    G f X f 22 2

    ) ( ) / (2 )v

    f f 22

    ( )v

    f f

    0( ) cos ( ) , ( ) 2 ( )

    t

    c C C v v tx t A t t t f x d

    ( )

    ( 2 ) ( )

    n

    n

    n

    d x t

    j f X fdt

    ( )( )sin ( )( )

    2

    qn n

    vc R

    n tA t tt

    A S

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    Post-detection SNR in FM (cont.)

    Therefore, the post-detection noise PSD can be written as

    and now the PSD for FM post detection noise is

    and the respective total noise power is

    2

    ( )2

    FM

    R T

    f fG f

    S B

    3( ) / 3WWD FM RN G f df W S

    22( ) ( )

    FM vG f f f

    ( )( )

    2

    q

    v

    R

    N ff

    S

    with

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    For PM we have

    For FM we have

    Under wideband condition and

    Destination S/N for PM and FM

    2

    2 2 2/ ,where

    /

    x

    D D x x

    R

    SS N S S

    W S

    2

    2

    3

    2

    // 3

    3 3

    x

    D D

    R

    R

    x x

    D

    f SS NW S

    f SS D S

    W W

    2

    3/

    4

    T

    D D x

    BS N S

    W

    1D Note that S

    D/N

    Dcan

    be increased just byincreasing deviation!

    2 3

    ( )

    2 3

    W

    D FMW

    R R

    f WN df

    S S

    ( )

    2

    W

    WD PM

    R R

    WN df

    S S

    1,2( 2) 2

    2 /(2 )

    mT m f W

    T

    B f W

    DW D B W

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    FM post-detection S/N with deemphases

    Deemphases filter (that is a lowpass filter connected afterdetector) can suppress noise further. FM post-detection noisePSD and total noise power without deemphases:

    With deemphases filter (for simplification assume W/Bde>>1):

    where

    2

    ( )2

    FM

    R T

    f fG f

    S B

    3

    ( )3

    W

    WD FM

    R

    WN G f df

    S

    3

    2 2

    /

    ( ) ( ) arctan /

    de

    W de

    WD FM de de R

    R de de

    W B

    B W WN G f H f df B W S

    S B B2

    21( )1 ( / )

    de

    de

    H ff B

    2 22

    2/

    /

    x x R

    D D x

    de R de de

    f S S S f fS N S

    B W S W B B

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    Example

    FM radio

    Without deemphases

    With deemphases

    Therefore if DSB or SSB system could be exchanged to FMsystem 640 fold transmission power savings could be achieved.Note, however that the required transmission bandwidth is nowabout 220 kHz /15 kHz = 15 times larger! Also, a problem is theFM threshold effect that we discuss next.

    75 kHz, 15 kHz, 5, 1/ 2, 2.1kHz

    x de

    f W D S B

    2

    21 2

    / 3

    (3 5 ) 38

    D D xS N D S

    2

    / ( / ) 640

    D D de x

    S N f B S

    R

    S

    W

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    Comparison of carrier wave

    modulation systems