Report - Mathematik 2: Korrekturanleitung - ksbg.ch...0.2x – 3 c#(0.1x + 0.05) = (2x – 1.6) c#0.35 + 0.05 | TU 0.2x –0.3x 0.15 = 0.7x 0.56 + 0.05 |TU – 0.1x – 0.15 = 0.7x – 0.51

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