Report - ABACUS-Übungsaufgaben · 2019-11-17 · J (g(x) - f(x))dx = = [Ix + 2cos(x) + 2cos J (l - 2sin(x)) dx — + 2cos = [Ix - (-2cos(x)) FE 9,02 FE Geg: a) b) f(x) — — 2 sin(x) :

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