Report - Anschluss Haupt-/Nebenträger · HT b NT a 2,c a 2,c β = 90° Figur 1: m HT< b Figur 2: mHT > bHT b HT m HT,v = m HT – b HT m NT m HT m NT h HT h HT m HT,v h NT h NT α 45°

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