56009 Modellaufgaben2heft en RZ.indd

39TestAS – Sample questions

The Mathematics, Computer Science and Natural Sciences Module is divided in two different subtests. You have a total of 145 minutes to solve the tasks. In the table below you can see how many tasks there are in each subtest and how much time is allowed.

To prepare for this, there are six tasks to solve for each subtest on the following pages. The tasks at the beginning are easier than those at the end. At the beginning of each subtest there is a short explanation about the type of the tasks, together with instructions on how to solve the tasks.

You can find the solutions starting at page 53.

Sample questions Mathematics, Computer Science and Natural Sciences Module

Subtest Amount of tasks Time allowed

Analysing Scientific Interrelationships 22 60 minutes

Understanding Formal Depictions 22 85 minutes

Total working time 145 minutes

56009_Modellaufgabenheft_EN_RZ.indd 39 26.06.13 14:17

40 TestAS – Sample questions

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Sample questions Solutions



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Sample question 1The observation results show that the main shoot and the side shoots of the untreated plant grow. If the tip of the main shoot is cut off, the main shoot stops growing. However, the phytohor-mone can be used to make a main shoot continue to grow after its tip has been cut off. The phytohormone hence promotes the growth of the main shoot. Statement I is therefore correct.The side shoots grow on the untreated plant and they also grow on the plant where the main shoot was cut off at the tip. If the phytohormone is applied, however, the side shoots stopped growing. The phytohormone hence hinders the growth of the side shoots. Statement II is hence also correct.The correct solution is therefore C.

Sample question 2Sequence A can be composed of the four parts which come about through division with the enzyme Ch. However, se-quence A cannot be composed of the four parts which come about through division with the enzyme Tr. Sequence A is therefore wrong.Sequence B is already wrong simply because it starts with the amino acid Gly and ends with Gly. The amino acid Leu has to form one end of the peptide X.Sequence C cannot be composed of the four parts which come about through division with the enzyme Ch. Sequence C is therefore wrong.Sequence D can be composed of the four parts which come about through division with the enzyme Ch. Sequence D can also be composed of the four parts which come about through division with the enzyme Tr. Sequence D is therefore correct.

Sample question 37KH�¿UVW�VWHS�LQ�VROYLQJ�WKLV�LWHP�LV�WR�GHWHUPLQH�ZKLFK�FXUYH�shows the temperature and which curve shows the amount of precipitation. Since only the thickly drawn curve also has nega-tive values (see region R3), it must be the temperature curve.In statement I, the annual precipitation amounts in the regions R1 and R4 are compared with one another. In region R1 the precipitation is greater than in region R4 in May, June and July. If we look at the year as a whole, however, the precipitation in region R4 is clearly greater than in region R1. Statement I is therefore wrong.Statement II can be checked by looking at the temperature curve. In region R1, the temperatures are the lowest in June and July and the highest in December and January. Region R1 must therefore be located south of the equator. Statement II is therefore correct.The correct solution is therefore B.

Sample question 4Potassium nitrate is a salt. The solubility of potassium nitrate must therefore be read from the left scale. One starts off from 50°C (on the horizontal temperature scale) and goes up verti-cally to the potassium nitrate curve, and from there horizontally to the left solubility scale. The solubility value for potassium nitrate readable here is greater than 70 g per 100 ml of water. Statement I is therefore incorrect.

The oxygen curve is steeper from 0°C to 20°C than from 20°C to 80°C. Hence a temperature change of x°C between 0°C and 20°C leads to a stronger change in solubility than between 20°C and 80°C. Statement II is hence correct.The correct solution is therefore B.

Sample question 5If one heats the right side of the tube, the mercury on this side expands to the left (pressing the air in the tube together). Since the mercury expands on the right side, its centre of gravity shifts, along with the centre of gravity of the entire tube, to the left. The left side of the tube goes down. Statement I is there-fore correct.However, the expansion of the mercury on the right side and the shift in the centre of gravity does not make the right side lighter. Statement II is hence incorrect.The correct solution is therefore A.

Sample question 6Let us assume the numbers on the upper edge (base edge) of the set square give the length in centimetres (cm). Then the distance between the “5” on the left side and the “5” on the right side – if measured with a normal set square or ruler – would measure 10.0 cm (5.0 + 5.0). When the set square has expanded by 1 percent, this distance measures 10.1 cm. If one uses this set square to measure an object which is exactly 10.0 cm long, this object will not reach all the way from the one “5” to the other “5”. The set square will accordingly show a value which is somewhat smaller than 10.0. Statement I is therefore correct. (This train of thought is somewhat easier to follow if one imagines an expansion of – for example – 50 per-cent.)If each of the three sides of the set square increases by 1 percent, then the overall circumference also increases by 1 percent. Statement II is therefore wrong.The correct solution is therefore A.

Solutions Mathematics, Computer Science and Natural Sciences Module



Understanding Formal Depictions

Sample question 1Statement I is incorrect: ,I�)�� D��WKHQ�WKH�¿UVW�TXHVWLRQ�LV�DQVZHUHG�³<(6´��7KHQ�\RX�come to the decision point below that. If F2 = a, then the se-cond question is also answered “YES” and you go right to the next decision point. If F3 = d, this question is also answered “YES” and you come to decision Y. Hence it is possible that F1 = a and Y is selected, not X. Statement II is also incorrect:,I�)�� E��\RX�JR�ULJKW�IURP�WKH�¿UVW�GHFLVLRQ�SRLQW��7KH�TXHVWLRQ in this decision point is “F2 = a?”. If F2 = b and you hence answer the question “NO”, you come directly to decision Z. Hence it is possible that F2 = b and Z is selected, not X.D is the correct solution.

Sample question 2Statement I is incorrect:,I�)�� E��WKH�DQVZHU�WR�WKH�¿UVW�TXHVWLRQ�LV�³12´��7KHQ�\RX�JHW�to the decision point on the right. If F2 = b, the answer to the second question is “NO”. Then you get to Z – even if F3 = c.Statement II is correct:The only way to decision Z is via the decision point at the top right (F2 = a?). If F2 = a, then the question is answered “YES” and you move to the decision point below, from where you can only go to X or Y.B is the correct solution.

Sample question 3

Bacteria in water: I S A Ec Increased Increased Normal Kp Increased Normal Increased Cf Normal Increased Normal Ea Normal Normal Increased

Statement I is correct:If I is increased, then you come to decision point Y, since you DQVZHU�WKH�¿UVW�TXHVWLRQ�³<(6´��,I�GHFLVLRQ�SRLQW�<�LV�ODEHOOHG�“Increase in concentration of S?”, an increase in S leads to the GHFLVLRQ� LQ� WKH�ÀRZ�FKDUW� WKDW� WKH�ZDWHU�VDPSOH�FRQWDLQV�(F��This is correct, for if the water contains Ec, I and S are increa-sed. However, if S is normal, then the question in decision point Y is answered “NO” and you come to the decision “Kp in water”. This is correct, for if the water contains Kp, I is increased and S is normal. If I is not increased, then you come to decision point X and the TXHVWLRQ�SRVHG�WKHUH�GHFLGHV�ZKHWKHU�WKH�ÀRZ�FKDUW�LV�FRUUHFW��+HQFH�WKH�ÀRZ�FKDUW�PD\�EH�FRUUHFW��Statement II is incorrect:If decision point X is labelled “Concentration of A normal?”, the ÀRZ�FKDUW�OHDGV�WR�WKH�ZURQJ�GHFLVLRQ�LQ�WZR�FDVHV��LI�(D�DUH�LQ�the water or if Cf are in the water.If Ea are in the water, then I is normal and A is increased. The TXHVWLRQ� LQ� WKH�¿UVW�GHFLVLRQ�SRLQW�PXVW� WKHUHIRUH�EH�DQVZH-red “NO” and you come to decision point X. If decision point X is labelled “Concentration of A normal?”, then the question in decision point X must be answered “NO” and you come to the wrong decision “Cf in the water”.

If Cf are in the water, then I is normal and A is normal. If deci-sion point X is labelled “Concentration of A normal?”, then the question in decision point X must be answered “YES” and you come to the wrong decision “Ea in water”.A is the correct solution.

Sample question 4

Bacteria in water: I S A Ec Increased Increased Normal Kp Increased Normal Increased Cf Normal Increased Normal Ea Normal Normal Increased

Statement I is incorrect:If the concentration of I is increased, then you come to decision SRLQW�<��VLQFH�\RX�DQVZHU�WKH�¿UVW�TXHVWLRQ�³<(6´��,I�GHFLVLRQ�point Y is labelled “Increase in concentration of A?”, an incre-DVH�LQ�$�OHDGV�WR�WKH�GHFLVLRQ�LQ�WKH�ÀRZ�FKDUW�WKDW�WKH�ZDWHU�sample contains Ec. This is incorrect, for if I and A are increa-sed, the water contains Kp.Statement II is correct:If I is not increased, you come to decision point X. If decision point X is labelled “Concentration of S normal?”, an increase in 6�OHDGV�WR�WKH�GHFLVLRQ�&I�LQ�WKH�ÀRZ�FKDUW��EHFDXVH�WKH�TXHV-tion is answered “NO”. This is correct because the combination of “I normal and S increased” means that the water contains Cf. ,I�6�KDG�D�QRUPDO�FRQFHQWUDWLRQ�OHYHO��WKH�ÀRZ�FKDUW�ZRXOG�OHDG�to the decision Ea. This is correct because the combination of “I normal and S normal” means that the water contains Ea.B is the correct solution.

Sample question 5Statement I is incorrect:If there are more than 10 participants, Room C is always cho-sen, even if customers are taking part in the meeting.Statement II is correct:,I� QR� FXVWRPHUV� DUH� WDNLQJ� SDUW�� WKHQ�� DFFRUGLQJ� WR� WKH� ÀRZ�chart, Room A is chosen if there are 4 or fewer participants, Room B is chosen for 5 to 10 participants, and Room C is cho-sen for more than 10 participants.B is the correct solution.

Sample question 6Statement I is correct: ,Q� WKH� FDVH� RI� �� SDUWLFLSDQWV�� WKH� TXHVWLRQ� ³13� �� "´� LV� answered “YES” and the question “NP > 10?” is answered “NO”, meaning that Room B is always chosen. Statement II is incorrect: Even if there are fewer than 5 people, Room B can still be cho-sen. For example, in the case of 4 participants, the question ³13��"´�LV�DQVZHUHG�³12´��,I�FXVWRPHUV�DUH�WDNLQJ�SDUW�LQ�WKH�meeting, the next question is answered “YES” and the meeting with 4 participants is held in Room B.A is the correct solution.

Solutions Mathematics, Computer Science and Natural Sciences Module



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56009 Modellaufgaben2heft en RZ.indd

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